jmc

We want to find the sum of the arithmetic series $301+303+\cdots +499$.

The common difference is 2, so the $n^{\text{th}}$ term in this arithmetic sequence is $301+2(n-1)=2n+299$. If $2n+299=499$, then $n=100$, so the number of terms in this sequence is 100.

The sum of an arithmetic series is equal to the average of the first and last term, multiplied by the number of terms, so the sum is $(301+499)/2\cdot 100=\boxed{40000}$.