Browse · MATH Print → jmc algebra intermediate Problem Define #N by the formula #N=.5(N)+1. Calculate #(#(#50)). Solution — click to reveal We have #(#(#50))=#(#(.5(50)+1))=#(#(26))=#(.5(26)+1)=#(14)=(.5(14)+1)=8. Final answer 8 ← Previous problem Next problem →