Browse · MATH Print → jmc algebra intermediate Problem If 4x−y+2z6x+3y+3z=7,=5, compute y. Solution — click to reveal Let w=2x+z. The equations become 2w−y3w+3y=7,=5. Subtracting twice the second equation from three times the first equation, 6w−3y−6w−6y=21−10⇒−9y=11. Thus y=−911. Final answer -\frac{11}{9} ← Previous problem Next problem →