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Bulgaria geometry
Problem
The diagonals and of the convex quadrilateral intersect at point . The points , , and from the segments , , and , respectively, are such that and . Let be the second intersection point of the circumcircles of and ; be the second intersection point of the circumcircles of and ; be the second intersection point of the circumcircles of and , and be the second intersection point of the circumcircles of and . Prove that the points , , and are concyclic.
Solution
It follows from the condition of the problem that and . Therefore . Let and be the midpoints of and , respectively. It follows that , which implies that the point lies on the circumcircle of . Analogously, belongs to the same circle.
Since and are also the midpoints of and , respectively, the above argument for the quadrilateral yields that and belong to the circumcircle of .
Since and are also the midpoints of and , respectively, the above argument for the quadrilateral yields that and belong to the circumcircle of .
Techniques
Angle chasingConstructions and lociMiquel point