Browse · MATH Print → jmc algebra junior Problem Given (a) x (b)=a2+2ab+b2, what is the value of (a) x (b) when a=3 and b=5? Solution — click to reveal Note that (a) x (b)=a2+2ab+b2=(a+b)2. Thus, (3) x (5)=(3+5)2=64. Final answer 64 ← Previous problem Next problem →