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Print49th Mathematical Olympiad in Ukraine
Ukraine number theory
Problem
a) Four positive integer numbers , , , satisfy the condition: every number , , , is a perfect cube. Are all the numbers , , , perfect cubes?
b) Five positive integer numbers , , , , satisfy the condition: every number , , , , is a perfect cube. Are all the numbers , , , , perfect cubes?
b) Five positive integer numbers , , , , satisfy the condition: every number , , , , is a perfect cube. Are all the numbers , , , , perfect cubes?
Solution
a) The example that it isn't necessary: , .
b) It shows that if a positive integer number has its square as a perfect cube of an integer number, then itself is a perfect cube of some integer number. Really, consider a factorization of into prime numbers , its square is , if is a perfect cube then for each we have to hold the condition which is equal to the condition . Hence, the number is a perfect cube.
As , then each of the numbers , , , , is a perfect cube.
b) It shows that if a positive integer number has its square as a perfect cube of an integer number, then itself is a perfect cube of some integer number. Really, consider a factorization of into prime numbers , its square is , if is a perfect cube then for each we have to hold the condition which is equal to the condition . Hence, the number is a perfect cube.
As , then each of the numbers , , , , is a perfect cube.
Final answer
a) No; for example a=c=2 and b=d=4. b) Yes; all five numbers must be perfect cubes.
Techniques
Factorization techniques