Skip to main content
OlympiadHQ

Browse · MathNet

Print

49th Mathematical Olympiad in Ukraine

Ukraine number theory

Problem

a) Four positive integer numbers , , , satisfy the condition: every number , , , is a perfect cube. Are all the numbers , , , perfect cubes?

b) Five positive integer numbers , , , , satisfy the condition: every number , , , , is a perfect cube. Are all the numbers , , , , perfect cubes?
Solution
a) The example that it isn't necessary: , .

b) It shows that if a positive integer number has its square as a perfect cube of an integer number, then itself is a perfect cube of some integer number. Really, consider a factorization of into prime numbers , its square is , if is a perfect cube then for each we have to hold the condition which is equal to the condition . Hence, the number is a perfect cube.

As , then each of the numbers , , , , is a perfect cube.
Final answer
a) No; for example a=c=2 and b=d=4. b) Yes; all five numbers must be perfect cubes.

Techniques

Factorization techniques