Browse · MATH Print → jmc algebra junior Problem If F(a,b,c,d)=ab+c×d, what is the value of x such that F(2,x,4,11)=300? Solution — click to reveal Plugging in, we have that 2x+4×11=300. This rearranges to 2x=256, or x=8. Final answer 8 ← Previous problem Next problem →