Given that 2x+2x+2x+2x=128, what is the value of (x+1)(x−1)?
Solution — click to reveal
First, we simplify the left side, and we have 2x+2x+2x+2x=4⋅2x=22⋅2x=2x+2.Noting that 128=27, our equation now is 2x+2=27, so x+2=7. Therefore, x=5, and (x+1)(x−1)=(6)(4)=24.