smc

Because $\frac{1}{x}<2$, $x>\frac{1}{2}$ when $x$ is positive. Because $\frac{1}{x}>-3$, $x<\frac{-1}{3}$ when $x$ is negative. $x$ can never be $0$, so these two inequalities cover all cases for the value of $x$. Thus, our answer is $\boxed{x>\frac{1}{2}\text{ or }x<-\frac{1}{3}}$.