jmc

Subtracting 9 from both sides of the equation, we have $x^2-5x-4=0$. The sum of the roots of this quadratic is negative its linear coefficient, which is $\boxed{5}$.

(The above is true because if a quadratic has roots $r$ and $s$, we have $(x-r)(x-s)=x^2-(r+s)+rs=0$.)