Browse · MATH Print → jmc algebra intermediate Problem The function f(x) satisfies b2f(a)=a2f(b)for all real numbers a and b. If f(2)=0, find f(2)f(5)−f(1). Solution — click to reveal Setting a=5 and b=2, we get 4f(5)=25f(2),so f(2)f(5)=425.Setting a=1 and b=2, we get 4f(1)=f(2),so f(2)f(1)=41. Hence, f(2)f(5)−f(1)=425−41=6. Final answer 6 ← Previous problem Next problem →