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Romania geometry
Problem
Let be a cyclic quadrilateral. The lines , meet at ; , at ; and , at . The perpendicular bisectors of , respectively , meet at , respectively at . Prove that passes through .
Solution
All poles and polars are considered with respect to the given circumcircle of . To start with, notice that line is the polar of and line is the polar of . As lies on the polar of , it follows that lies on the polar of . The pole of the line is the point at infinity on the direction , as is a diameter line. Thus the polar of is the line , implying that is tangent to the given circle at . Similar considerations show that is tangent to the given circle at , hence proving the thesis.
Techniques
Cyclic quadrilateralsTangentsPolar triangles, harmonic conjugates