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imc

prealgebra junior

Problem

What value of

x

satisfies

x - \frac{3}{4} = \frac{5}{12} - \frac{1}{3} ?

(A)

- \frac{2}{3}

(B)

\frac{7}{36}

(C)

\frac{7}{12}

(D)

\frac{2}{3}

(E)

\frac{5}{6}

Solution

Adding

\frac{3}{4}

to both sides,

x = \frac{5}{12} - \frac{1}{3} + \frac{3}{4} = \frac{5}{12} - \frac{4}{12} + \frac{9}{12} = \frac{5}{6}

.

Final answer

E