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jmc

counting and probability intermediate

Problem

How many three-digit whole numbers have no 7's and no 9's as digits?
Solution
In order to be a three-digit number, the first digit cannot be 0, so there are normally 9 choices for the hundreds digit. But it also cannot be 7 or 9, so there are actually only 7 choices for the hundreds digit, and then 8 digits each for the units and tens digits. So, there are such numbers.
Final answer
448