Browse · harp Print → jmc geometry junior Problem If ∠A=60∘, ∠E=40∘ and ∠C=30∘, then ∠BDC= (A) 40∘ (B) 50∘ (C) 60∘ (D) 70∘ Solution — click to reveal The sum of the angles in a triangle is 180∘. We can find ∠ABE=80∘, so ∠CBD=180−80=100∘. ∠BDC=180−100−30=50∘ Final answer B ← Previous problem Next problem →
