Evaluate 3+x(3+x)-3^2x-3+x^2 for x=-2.

3+x(3+x)-3^2x-3+x^2=3+(-2)(3+(-2))-3^2-2-3+(-2)^2=-8-1=8

jmc

algebra junior

Problem

Evaluate

\frac{3 + x ( 3 + x ) - 3 ^{2}}{x - 3 + x ^{2}}

for

x = - 2

Solution

\frac{3 + x ( 3 + x ) - 3 ^{2}}{x - 3 + x ^{2}} = \frac{3 + ( - 2 ) ( 3 + ( - 2 )) - 3 ^{2}}{- 2 - 3 + ( - 2 ) ^{2}} = \frac{- 8}{- 1} = 8

Final answer