Browse · MATH Print → jmc algebra intermediate Problem Expand (2x5+3x2)(x4−4x2+3x−8). Solution — click to reveal Using the distributive property, we have (2x5+3x2)(x4−4x2+3x−8)=2x5(x4−4x2+3x−8)+3x2(x4−4x2+3x−8)=2x9−8x7+6x6−16x5+3x6−12x4+9x3−24x2=2x9−8x7+9x6−16x5−12x4+9x3−24x2. Final answer 2x^9 - 8x^7 + 9x^6 - 16x^5 - 12x^4 + 9x^3 - 24x^2 ← Previous problem Next problem →