jmc

The lateral surface area of a cylindrical tube is equal to $2\pi rh$, where $r$ is the radius and $h$ is the height of the tube. Since we are told that the height is 6 cm and the lateral surface area is equal to $48\pi$ square cm, we have the equation $2\cdot \pi \cdot r\cdot 6=48\pi \Rightarrow r=4$. The volume of the tube is equal to $\pi \cdot r^2\cdot h=\pi \cdot 4^2\cdot 6=\boxed{96\pi }$ cubic cm.