jmc

We see that the endpoints of the major axis of the ellipse are $(0,-1)$ and $(6,-1)$, and the endpoints of the minor axis of the ellipse are $(3,1)$ and $(3,-3)$. Then, the center of the ellipse is the midpoint of the two axes, which is $(3,-1)$.

The lengths of the major and minor axis are $6$ and $4$, respectively, so the distance between the foci is $\sqrt{6^2-4^2}=2\sqrt{5}.$ It follows that each focus is $\sqrt{5}$ away from the center, $(3,-1),$ along the major (horizontal) axis. Therefore, the focus with the larger $x$-coordinate must be $\boxed{(3+\sqrt{5},-1)}.$