Browse · MATH Print → jmc algebra junior Problem If x+y=137 and x−y=911, what is the value of x2−y2? Express your answer as a common fraction. Solution — click to reveal We know that x2−y2=(x+y)(x−y). Substituting, we see that x2−y2=137⋅911=1691. Final answer \frac{1}{169} ← Previous problem Next problem →