jmc

Since the problem only asks for the final image of point $Q$, we only need to look at point $Q$ with respect to point $M$. We plot the two points below and connect them:

When we rotate $Q$ $270^{\circ }$ clockwise about $M$, we arrive at $Q^{\prime }=(0,5)$:



Reflecting $Q^{\prime }=(0,5)$ about the line $x=1$ yields $Q^{\prime \prime }=\boxed{(2,5)}$. Notice that entirely by coincidence, this is the same as point $M$.