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smc

counting and probability intermediate

Problem

A speaker talked for sixty minutes to a full auditorium. Twenty percent of the audience heard the entire talk and ten percent slept through the entire talk. Half of the remainder heard one third of the talk and the other half heard two thirds of the talk. What was the average number of minutes of the talk heard by members of the audience?
(A)
(B)
(C)
(D)
Solution
Assume that there are people in the audience. people heard minutes of the talk, for a total of minutes heard. people heard minutes. people heard minutes of the talk, for a total of minutes. people heard minutes of the talk, for a total of minutes. Altogether, there were minutes heard among people. Thus, the average is minutes, and the answer is .
Final answer
D