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smc

prealgebra senior

Problem

Let

n = 8^{2022}

. Which of the following is equal to

\frac{n}{4} ?

(A)

4^{1010}

(B)

2^{2022}

(C)

8^{2018}

(D)

4^{3031}

(E)

4^{3032}

Solution

We have

n = 8^{2022} = (8^{\frac{2}{3}})^{3033} = 4^{3033} .

Therefore,

\frac{n}{4} = 4^{3032} .

Final answer

E