We use the order of operations here to get align* -15+9 (6 3) &= -15+9 2 &= -15+18 &= 3 3 align*

jmc

prealgebra junior

Problem

- 15 + 9 \times (6 \div 3) =

(A)

- 48

(B)

- 12

(C)

- 3

(D)

3

Solution

We use the order of operations here to get

- 15 + 9 \times (6 \div 3) = - 15 + 9 \times 2 = - 15 + 18 = 3 \to 3

Final answer