Each of the fractions simplify to 110, so this sum is align* 110+110+110 &= 310 &= .3 .3 align*

jmc

prealgebra junior

Problem

\frac{1}{10} + \frac{2}{20} + \frac{3}{30} =

(A)

.1

(B)

.123

(C)

.2

(D)

.3

Solution

Each of the fractions simplify to

\frac{1}{10}

, so this sum is

\frac{1}{10} + \frac{1}{10} + \frac{1}{10} = \frac{3}{10} = .3 \to .3

Final answer