Browse · MATH Print → jmc algebra intermediate Problem Find the ordered pair (a,b) of real numbers for which x2+ax+b has a non-real root whose cube is 343. Solution — click to reveal We want x to satisfy x3=343. Then x3−343=0, which factors as (x−7)(x2+7x+49)=0. Thus, (a,b)=(7,49). Final answer (7,49) ← Previous problem Next problem →