Browse · MATH Print → jmc algebra junior Problem When simplified, what is the value of 3×321+12÷3×2−423? Solution — click to reveal We first note that 3×321=321×321=321+21=31=3 and 43/2=(22)23=22⋅23=23=8, so 3×321+12÷3×2−423=3+12÷3×2−8=3+4×2−8=3+8−8=3. Final answer 3 ← Previous problem Next problem →