Browse · MATH Print → jmc algebra intermediate Problem What is the sum of 1+2+4+8+16+⋯+1024? Solution — click to reveal This is a finite geometric series with first term 1, common ratio 2 and 11 terms. Thus the sum is: 1−21(1−211)=−11−211=211−1=2048−1=2047. Final answer 2047 ← Previous problem Next problem →