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62nd Ukrainian National Mathematical Olympiad

Ukraine geometry

Problem

Let be the incenter of the triangle , and be any point on the arc of the circumscribed circle. On the tangent to the circumscribed circle of the triangle at the point points and were selected so that and . Prove that the circumcircle of the triangle is tangent to . (Mykhailo Shtandenko)

problem
Fig. 13

problem
Fig. 14
Solution
Mark the midpoints of the arcs , , that do not contain other points, by the points , , respectively (fig. 13). It is clear that and lie on and respectively. Then. Fig. 13

Archimedes' Lemma. If a circle is inscribed in a segment of another circle bounded by the chord and touches the arc at the point and the chords at the point then the line is a bisector (fig. 14). Fig. 14

Techniques

Triangle centers: centroid, incenter, circumcenter, orthocenter, Euler line, nine-point circleTangentsAngle chasing