Browse · MATH Print → jmc number theory intermediate Problem If 4x≡8(mod20) and 3x≡16(mod20), then what is the remainder when x2 is divided by 20? Solution — click to reveal We have x≡4x−3x≡8−16≡−8(mod20).Therefore, x2≡(−8)2=64≡4(mod20). Final answer 4 ← Previous problem Next problem →