Browse · harp
Printsmc
prealgebra intermediate
Problem
If and are digits for which then
(A)
(B)
(C)
(D)
Solution
Working from right to left, we see that . Clearly if is a single digit integer, this cannot be possible. Therefore, there must be some borrowing from . Borrow from the digit , and you get , giving . Since was borrowed from , we have from the tens column . Again for single digit integers this will not work. Again, borrow from , giving . Solving for : Finally, since was borrowed from the hundreds column, we have , giving . As a check, the problem is , which is a true sentence. The desired quantity is , and the answer is .
Final answer
D