Browse · MATH Print → jmc algebra intermediate Problem Find the coefficient of x49 in the expansion of (x+1)(x+3)(x+5)⋯(x+95)(x+97)(x+99). Solution — click to reveal By Vieta's formulas, the coefficient of x49 is the negative of the sum of the roots, which is −(−1−3−5−⋯−95−97−99)=2500. Final answer 2500 ← Previous problem Next problem →