jmc

Let $a$ be Alex's age, $b$ be Bob's age, $c$ be Camille's age, and $d$ be Danielle's age. We can express the information given in the problem with the following system of linear equations: $$\begin{array}{rl}a+b+d& =14c\\ a+b& =6c\\ b& =d-a-2\end{array}$$ Substituting for $a+b$ in terms of $c$ into the first equation gives $d=8c$. Rearranging the third equation gives $a+b=d-2$, and substituting for $a+b$ in terms of $c$ gives $d-2=6c$. Substituting $8c$ for $d$ gives $8c-2=6c$, so $c=\boxed{1}$.