If m=caba-b, then b equals:

m=caba-b ma-mb=cab ma=b(m+ac) b=mam+ca

smc

algebra intermediate

Problem

m = \frac{c ab}{a - b}

, then

b

equals:

(A)

f r a c (m (a - b), c a)

(B)

\frac{c ab - ma}{- m}

(C)

\frac{1}{1 + c}

(D)

\frac{ma}{m + c a}

Solution

m = \frac{c ab}{a - b} ⟹ ma - mb = c ab ⟹ ma = b (m + a c) ⟹ b = \frac{ma}{m + c a}

Final answer