Browse · MATH Print → jmc algebra junior Problem Assuming x=0, simplify x⋅x12⋅14xx4⋅3x35. Solution — click to reveal We have x⋅x12⋅14xx4⋅3x35=x2⋅14x⋅3x12⋅x4⋅35=(3⋅2⋅7)(x2⋅x⋅x)(4⋅3)⋅(5⋅7)⋅x4=2⋅3⋅72⋅2⋅3⋅5⋅7⋅x4x4=2⋅5=10. Final answer 10 ← Previous problem Next problem →