jmc

The midpoint of segment $s_1$ can be found using the midpoint formula: $\left(\frac{1+7}{2},\frac{2+10}{2}\right)=(4,6).$ The midpoint of $s_2$ is the translation of the midpoint of $s_1$ be $3$ units to the right and $2$ units down. Thus its coordinates are $(4+3,6-2)=\boxed{(7,4)}.$