jmc

We will complete the square to rewrite the given expression in standard form. Factoring out a -2 from the first two terms, we have $$-2(x^2+10x)-53$$In order for the expression inside the parenthesis to be a perfect square, we need to add and subtract $(10/2{)}^2=25$ inside the parenthesis: $$-2(x^2+10x+25-25)-53=-2(x+5{)}^2-3$$Thus, $a=-2$, $d=5$, and $e=-3$, so the sum $a+d+e$ is $-2+5+(-3)=\boxed{0}$.