jmc

Reading from the equation, we see that the center of the ellipse is $(6,3),$ the length of the semimajor axis is $\sqrt{25}=5,$ and the length of the semiminor axis is $\sqrt{9}=3.$ Then, the distance from the center to each of the foci must be $\sqrt{5^2-3^2}=4.$

The major axis is parallel to the $x$-axis, so the coordinates of the two foci are $(6-4,3)=(2,3)$ and $(6+4,3)=(10,3).$ The one with the larger $x$-coordinate is $\boxed{(10,3)}.$