Browse · MATH Print → jmc algebra intermediate Problem The expression 6y2−y−51 can be rewritten as (3Ay+B)(y−C), where A, B, and C are positive integers. Find (AC)2−B. Solution — click to reveal The expression 6y2−y−51 can be rewritten as (6y+17)(y−3). Therefore, A=2, B=17, and C=3. Thus, (AC)2−B=(2×3)2−17=19. Final answer 19 ← Previous problem Next problem →