Browse · harp Print → smc geometry intermediate Problem In the adjoining figure, CDE is an equilateral triangle and ABCD and DEFG are squares. The measure of ∠GDA is (A) 90∘ (B) 105∘ (C) 120∘ (D) 135∘ Solution — click to reveal m∠GDA=360∘−90∘−60∘−90∘=120∘⇒120∘ Final answer C ← Previous problem Next problem →