Browse · MATH Print → jmc algebra intermediate Problem Compute the sum of the geometric series −1+2−4+8−⋯+512. Solution — click to reveal The first term is −1, the common ratio is −2, and there are 10 terms, so the sum equals −2−1(−1)((−2)10−1)=−3−1023=341. Final answer 341 ← Previous problem Next problem →