100 19.98 1.998 1000=

19.98100=1998 1.9981000=1998 19981998=(1998)^2=(1998)^2

jmc

prealgebra junior

Problem

100 \times 19.98 \times 1.998 \times 1000 =

(A)

(1.998)^{2}

(B)

(19.98)^{2}

(C)

(199.8)^{2}

(D)

(1998)^{2}

Solution

19.98 \times 100 = 1998

1.998 \times 1000 = 1998

1998 \times 1998 = (1998)^{2} = (1998)^{2}

Final answer