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Question

The length of a rectangle is 3x+10 feet and its width is x+12 feet. If the perimeter of the rectangle is 76 feet, how many square feet are in the area of the rectangle?

Accepted Answer

The perimeter of a rectangle with dimensions l and w is 2(l+w). Setting 2(3x+10+x+12) equal to 76, we find 4x+22=38, which implies x=4 feet. The area of the rectangle is (3x+10)(x+12)=(3(4)+10)(4+12)=352 square feet.