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algebra intermediate
Problem
The sequence 1,000,000; 500,000; 250,000 and so on, is made by repeatedly dividing by 2. What is the last integer in this sequence?
Solution
Repeatedly dividing by 2, we find the next terms in the sequence to be 125000, 62500, 31250, 15625,... 15625 is no longer a multiple of 2, so when we divide by 2 again, we will not get an integer, nor will it be a multiple of 2. Thus, no number in the sequence after 15625 can be an integer. Thus, our answer is .
Final answer
15625