Browse · MATH Print → jmc algebra intermediate Problem Simplify \root3\ofx\root3\ofx\root3\ofxx. Express your answer in simplest radical form in terms of x. Solution — click to reveal We have\root3\ofx\root3\ofx\root3\ofxx=(x(x(x⋅x21)31)31)31=(x(x(x23)31)31)31=(x(x⋅x21)31)31=(x(x23)31)31=(x⋅x21)31=(x23)31=x21=x. Final answer \sqrt{x} ← Previous problem Next problem →