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Print69th Belarusian Mathematical Olympiad
Belarus geometry
Problem
A point is chosen in the interior of the side of the triangle . The points and are symmetric to with respect to the vertices and respectively. The circumcircles of the triangles and intersect at the points and . The ray intersects the segment at the point and the ray intersects the segment at the point . Prove that the lines and are parallel.

Solution
First we will prove that point lies on the line . Let the line intersect the circumcircle of the triangle at points and .
Since , the equality implies , and therefore the points , , and are concyclic, consequently .
From the circumcircles of and we obtain and .
The quadrilateral is cyclic, since Therefore, , whence and .
Since , the equality implies , and therefore the points , , and are concyclic, consequently .
From the circumcircles of and we obtain and .
The quadrilateral is cyclic, since Therefore, , whence and .
Techniques
Cyclic quadrilateralsRadical axis theoremAngle chasing