Browse · MATH Print → jmc algebra junior Problem If F(a,b,c,d)=ab+c×d, what is the value of b such that F(6,b,4,3)=48? Solution — click to reveal We are given that F(6,b,4,3)=6b+4×3=48. This rearranges to 6b=36, or b=2. Final answer 2 ← Previous problem Next problem →