Browse · MATH Print → jmc algebra intermediate Problem Define #N by the formula #N=.5(N)+1. Calculate #(#(#58)). Solution — click to reveal We have #(#(#58))=#(#(.5(58)+1))=#(#(30))=#(.5(30)+1)=#(16)=(.5(16)+1)=9. Final answer 9 ← Previous problem Next problem →