Browse · MATH
Printjmc
algebra senior
Problem
Fake gold bricks are made by covering concrete cubes with gold paint, so the cost of the paint is proportional to their surface area while the cost of the concrete is proportional to their volume. If a 1 inch cube costs \1.30\, then how much would a 3 inch cube cost?
Solution
Let be the cost per square inch of gold paint, and let be the cost per cubic inch of concrete. Since a 1 inch cube has surface area 6 and volume 1 its total price will be dollars. Similarly, a 2 inch cube has surface area 24 and volume 8 , so its total price will be dollars. We are given that Subtracting 4 times the first equation from the second gives 4y=\1.60y=\. Hence 6x=\0.90x=\. Since a 3 inch cube has surface area 54 and volume 27 , its total price will be a total of 54(\0.15)+27(\0.40)=\boxed{\18.90}$.
Final answer
\$18.90