What is the value of (2112-2021)^2169?

We have (2112-2021)^2169=91^2169=91^213^2=(9113)^2=7^2=49.

smc

prealgebra senior

Problem

What is the value of

\frac{( 2112 - 2021 ) ^{2}}{169}

(A)

7

(B)

21

(C)

49

(D)

64

Solution

We have

\frac{( 2112 - 2021 ) ^{2}}{169} = \frac{9 1 ^{2}}{169} = \frac{9 1 ^{2}}{1 3 ^{2}} = (\frac{91}{13})^{2} = 7^{2} = 49 .

Final answer